← Prev Question Next Question →
2.2k views
The analog signal m(t) is given below m(t) = 4 cos 100 pt + 8 sin 200 pt + cos 300 pt, the Nyquist sampling rate will be: (1) 1/100 (2) 1/200 (3) 1/300 (4) 1/600 
by
Request Answer

Please log in or register to answer this question.

1 Answer

0 votes

The analog signal m(t) is given below m(t) = 4 cos 100 pt + 8 sin 200 pt + cos 300 pt, the Nyquist sampling rate will be: 1/300

by
Ask a Question